Circle geometry focuses on the properties and relationships involving circles, such as chords, tangents, diameters, radii, and angles in circles.
Question: Given a circle with centre O, and chord AB = 6 units. If the perpendicular from O to AB meets AB at point M and OM = 2 units, find the radius of the circle.
Step 1: Write down what is given.
AB = 6,quad OM = 2
Step 2: Draw a diagram with O, A, B, M.
Step 3: Since OM ⟂ AB and M is the midpoint of AB,
AM = MB = 3
Step 4: Use Pythagoras’ theorem in triangle OMA.
OA^2 = OM^2 + AM^2
Step 5: Substitute.
OA^2 = 2^2 + 3^2
OA^2 = 4 + 9
OA^2 = 13
OA = sqrt{13}
Step 6: The radius is sqrt{13} units.
Exam Tip: Always mark the centre, radius, and any given angles or perpendiculars on your diagram.
Common mistake: Forgetting that the perpendicular from the centre bisects the chord.
A tangent is a straight line that touches a circle at exactly one point, called the point of contact. A chord is a line segment joining any two points on a circle.
Question: In the diagram, AB is a tangent to the circle at point A and AC is a chord. If AB = 8\ units and both AB and AD are tangents from point A, find the length of AD.
Step 1: Tangents from the same external point are equal.
AB = AD = 8
Step 2: Final answer: AD = 8\ units .
Exam Tip: Use the tangent properties to establish lengths and relationships quickly.
Common mistake: Confusing a secant (line intersecting the circle at two points) with a tangent.
.png)
A cyclic quadrilateral is a quadrilateral whose vertices all lie on a single circle. This circle is called the circumcircle.
Question: Given a cyclic quadrilateral ABCD, if angle A = 75°, find angle C.
Step 1: Opposite angles in a cyclic quadrilateral are supplementary.
angle A + angle C = 180^\circ
Step 2: Substitute angle A = 75^\circ
75^\circ + angle C = 180^\circ
angle C = 180^\circ - 75^\circ
angle C = 105^\circ
Common mistake: Only one pair of opposite angles must sum to 180°, but both pairs do.
Exam Tip: Always check if all vertices are on the circle before using these properties.
Triangles are similar if their corresponding angles are equal and their corresponding sides are in proportion.
Question: Triangle ABC is similar to triangle DEF, and AB = 4\ units , BC = 6\ units , DE = 8\ units . Find the length of EF.
Step 1: Write the proportion.
\dfrac{AB}{DE} = \dfrac{BC}{EF}
Step 2: Substitute known values.
\dfrac{4}{8} = \dfrac{6}{EF}
Step 3: Cross-multiply.
4 \times EF = 8 \times 6
4EF = 48
EF = \dfrac{48}{4}
EF = 12\ units
Common mistake: Not matching corresponding sides correctly.
Exam Tip: Mark equal angles and set up side ratios correctly.
Triangles are congruent if all their corresponding sides and angles are equal.
Question: Prove that triangle ABC is congruent to triangle DEF if:
AB = DE = 7 units,
BC = EF = 9 units,
AC = DF = 5 units
Step 1: State the SSS rule.
If all three sides are equal, the triangles are congruent.
AB = DE,\ BC = EF,\ AC = DF
Therefore, triangle ABC ≅ triangle DEF by SSS.
Common mistake: Using AAA (Angle-Angle-Angle) for congruency – AAA only gives similarity, not congruency.
The midpoint theorem states that the line segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
Question: In triangle ABC, D and E are midpoints of AB and AC. If BC = 10 units, find DE.
Step 1: By the midpoint theorem,
DE = \frac{1}{2} BC
DE = \frac{1}{2} \times 10
DE = 5\ units
Exam Tip: In coordinate geometry, use the midpoint formula for accuracy.
Question: Given points A(2, 3) and B(6, 7). Find the midpoint M.
Step 1: Use the midpoint formula.
M \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
Step 2: Substitute values.
M \left( \frac{2+6}{2}, \frac{3+7}{2} \right)
M(4, 5)
.png)
In Euclidean geometry, a “rider” refers to a deductive geometry problem, often requiring use of circle, triangle and quadrilateral properties. Formal geometric proofs involve logical application of theorems and axioms with clear reasons for each statement.
Question: In circle O, AB is a diameter. Prove that angle ACB = 90° if C lies on the circle.
Step 1: Statement: AB is a diameter (given).
Step 2: Angle subtended by diameter at circumference is 90° (theorem).
angle ACB = 90^\circ
Reason: Angle in a semicircle.
Exam Tip: Always write the reason for each statement, using curriculum-approved language.
Proofs are the foundation for solving riders. They help justify why certain properties and relationships hold, which is required in all advanced geometry tasks. Be familiar with common theorems such as the congruent triangles rules, the angle properties of circles and cyclic quadrilaterals, and the midpoint theorem, as these are commonly tested.
Success in Euclidean geometry depends on understanding and applying key theorems with clear logical reasoning and correct notation. Use diagrams to visualise problems, show every mathematical step clearly, and always provide full reasons for each step during proofs. Practise with multiple examples and past paper questions to gain confidence and accuracy in problem-solving.